(5x+4)(4x^2-19x-5)=0

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Solution for (5x+4)(4x^2-19x-5)=0 equation: 


Simplifying
(5x + 4)(4x2 + -19x + -5) = 0

Reorder the terms:
(4 + 5x)(4x2 + -19x + -5) = 0

Reorder the terms:
(4 + 5x)(-5 + -19x + 4x2) = 0

Multiply (4 + 5x) * (-5 + -19x + 4x2)
(4(-5 + -19x + 4x2) + 5x * (-5 + -19x + 4x2)) = 0
((-5 * 4 + -19x * 4 + 4x2 * 4) + 5x * (-5 + -19x + 4x2)) = 0
((-20 + -76x + 16x2) + 5x * (-5 + -19x + 4x2)) = 0
(-20 + -76x + 16x2 + (-5 * 5x + -19x * 5x + 4x2 * 5x)) = 0
(-20 + -76x + 16x2 + (-25x + -95x2 + 20x3)) = 0

Reorder the terms:
(-20 + -76x + -25x + 16x2 + -95x2 + 20x3) = 0

Combine like terms: -76x + -25x = -101x
(-20 + -101x + 16x2 + -95x2 + 20x3) = 0

Combine like terms: 16x2 + -95x2 = -79x2
(-20 + -101x + -79x2 + 20x3) = 0

Solving
-20 + -101x + -79x2 + 20x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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